問題描述

引用的是jquery-2.1.4.min.js，數(shù)據(jù)提交成功了，但是不跳轉(zhuǎn)。數(shù)據(jù)庫測(cè)試也有記錄。JS代碼function Login() { $.ajax({type: "POST",//方法url: "aph/logingo.php" ,//表單接收urldata: $('#form1').serialize(),success: function (data) { var result=document.getElementById("Result"); //提交成功 result.innerHTML=data[0].result; if (data[0].result == "登陸成功") { result.innerHTML="登陸成功";setTimeout("window.location.,2000); }else if (data[0].result == "fail") {result.innerHTML="<a style='color:red'>賬號(hào)或密碼錯(cuò)誤</a>"; }},error : function(data) { //提交失敗的提示詞或者其他反饋代碼 var result=document.getElementById("Result"); result.innerHTML="<a style='color:red'>網(wǎng)絡(luò)連接失敗</a>";} });}PHP代碼<?php//error_reporting(-1); //打印出所有的 錯(cuò)誤信息header("Content-type:application/json;chartset=uft-8");$username = $_POST["username"];//獲取表單POST過來的用戶名$passs = $_POST["pass"];//獲取表單POST過來的密碼//$addkey = $_POST['logcode'];//8位KEY //表單過濾$user = trim($username);//過濾空格$psw = trim($passs);//過濾空格 //開始判斷if($user == "" && $psw == ""){ echo "[{"result":"<a style='color:red'>賬號(hào)和密碼都沒填呢！</a>"}]";}else if ($user == "") { echo "[{"result":"<a style='color:red'>賬號(hào)還沒填呢</a>"}]";}else if ($psw == "") { echo "[{"result":"<a style='color:red'>密碼還沒填呢</a>"}]";}else{ //校驗(yàn)MD5密碼 $md5psw = MD5($psw); include_once($_SERVER['DOCUMENT_ROOT'].'/config/db.php');//鏈接數(shù)據(jù)庫配置文件$sql = "SELECT * FROM add_user WHERE username='$_POST[username]' and pass='$md5psw'";$result = $db->query($sql);$row = $result->fetch_assoc();session_start();$_SESSION['username'] = $row['username'];$_SESSION['userid'] = $row['id'];if ($row) { echo "[{"result":"驗(yàn)證成功"}]"; }else{echo "[{"result":"fail"}]"; }}?>

問題解答

自己已經(jīng)解決，謝謝。